Need reviewer: No fastdebug builds by default at at
Thu Feb 3 18:41:15 UTC 2011


webrev looks good.

RE script takes product or fastdebug as a parameter and pass it to make:

  if [ $build_variant_arg = "fastdebug" ]; then
    gnumake all SKIP_PRODUCT_BUILD=true $newarg $OP $JUNIT
  elif [ $build_variant_arg = "product" ]; then
    gnumake all SKIP_FASTDEBUG_BUILD=true $newarg $OP $JUNIT
    gnumake all $newarg $OP $JUNIT

Instead of settting SKIP_FASTDEBUG_BUILD=false,
does setting SKIP_PRODUCT_BUILD=true (first if condition) cause none of 
product and fastdebug get built?


David Katleman (Oracle) wrote:
> Looks fine Kelly.
>        Dave
> Kelly O'Hair wrote:
>> Need reviewer: No fastdebug builds by default
>> One word change. Default builds from the root will be faster due to 
>> not building the fastdebug images.
>> This change is in the open repository but will only impact our closed 
>> jdk builds.
>> Currently when building the openjdk from the top of the forest, it 
>> only builds one image, the so
>> called "product" image. This change does the same for closed jdk7 
>> builds.
>> FYI.. The fastdebug builds are built with slightly lower native 
>> compiler optimization levels,
>> all assert checking enabled, and include more debug information. The 
>> java classes may also
>> include local variable debugging information. These are mostly for 
>> developers but can be used
>> to isolate runtime issues in a jdk.
>> Anyone wanting both builds or the old behavior would need to use:
>>    make SKIP_FASTDEBUG_BUILD=false
>> 7014634: By default, only build the product bits with a closed jdk 
>> build (like openjdk does)
>> -kto

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