RFR 8027316 Distinct operation on an unordered stream should not be a barrier
paul.sandoz at oracle.com
Fri Nov 1 16:34:58 UTC 2013
On Oct 30, 2013, at 5:54 PM, Henry Jen <henry.jen at oracle.com> wrote:
> Looks good to me.
> In the test,
>> Integer one = Stream.iterate(1, i -> i + 1).unordered().parallel().distinct().findAny().get();
>> assertEquals(one.intValue(), 1);
> The implementation is probably make sure this will return 1, but is that what we spec to do? I sort of think it can have various values depends on how many working threads and their scheduling.
Doh! you are correct, sorry, i made a silly mistake and had this in my head "Stream.iterate(1, i -> i + 1).parallel().distinct().findFirst().get()" when i responded. This test is failing in some cases exactly for the reasons you give.
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