how to tell 2 methods are override-equivalent
jonathan.gibbons at oracle.com
Tue Mar 21 21:28:09 UTC 2017
Use Element.asType() to move from the Element world to the TypeMirror world.
Use Types.asElement(TypeMirror) to go in the reverse direction, from a
TypeMirror to an Element.
but note the reverse direction is lossy and may throw exceptions:
e.g. for type "int", there is no direct element equivalent; for
type List<String>, the element will be the declaration List<T>
On 3/16/17 8:15 PM, Hamlin Li wrote:
> ( I'm not sure if this is the right alias to ask the question, please
> help forward if necessary. )
> I have a question about telling whether one method is subsignature of
> another one. My situation is,
> 1. there is a TypeElement *t1 *which represents java.net.URL, and a
> ExecutableElement *m1* which represents
> 2. there is a String *t2* which is "java.net.URL", and another String
> *m2 *which is "getContent(java.lang.Class)".
> The difference between m1 and m2 is that, m1 is an instance of
> ExecutableElement, m2 is an instance of String; there is a wildcard
> type argument in m1.
> Is there a way to tell whether m1 and m2 are override-equivalent, m2
> is subsignature of m1?
> I suppose I should use
> javax.lang.model.util.Types.isSubsignature(ExecutableType m1,
> ExecutableType m2), but I don't know how can I convert
> ExecutableElement *m1* and String *m2* to**ExecutableType.
> Or I'm in wrong direction?
> Thank you
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